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1120112202300 = 22352721329359563
BaseRepresentation
bin10000010011001011111…
…000111101001000111100
310222002012112201111121020
4100103023320331020330
5121322442210433200
62214323351504140
7143632265424600
oct20231370751074
93862175644536
101120112202300
113a2045156293
12161103388050
138181a7a97b0
143c2dc639500
151e20b4d1ea0
hex104cbe3d23c

1120112202300 has 864 divisors, whose sum is σ = 4219154956800. Its totient is φ = 227142236160.

The previous prime is 1120112202277. The next prime is 1120112202317. The reversal of 1120112202300 is 32022110211.

It is a super-2 number, since 2×11201122023002 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 1120112202300.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 287 ways as a sum of consecutive naturals, for example, 1989541819 + ... + 1989542381.

It is an arithmetic number, because the mean of its divisors is an integer number (4883281200).

Almost surely, 21120112202300 is an apocalyptic number.

1120112202300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1120112202300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2109577478400).

1120112202300 is an abundant number, since it is smaller than the sum of its proper divisors (3099042754500).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1120112202300 is a wasteful number, since it uses less digits than its factorization.

1120112202300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 995 (or 981 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 1120112202300 its reverse (32022110211), we get a palindrome (1152134312511).

The spelling of 1120112202300 in words is "one trillion, one hundred twenty billion, one hundred twelve million, two hundred two thousand, three hundred".