112011403433 has 2 divisors, whose sum is σ = 112011403434. Its totient is φ = 112011403432.

The previous prime is 112011403429. The next prime is 112011403453. The reversal of 112011403433 is 334304110211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 111878877289 + 132526144 = 334483^2 + 11512^2 .

It is a cyclic number.

It is not a de Polignac number, because 112011403433 - 2² = 112011403429 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 112011403399 and 112011403408.

It is not a weakly prime, because it can be changed into another prime (112011403453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56005701716 + 56005701717.

It is an arithmetic number, because the mean of its divisors is an integer number (56005701717).

Almost surely, 2^112011403433 is an apocalyptic number.

It is an amenable number.

112011403433 is a deficient number, since it is larger than the sum of its proper divisors (1).

112011403433 is an equidigital number, since it uses as much as digits as its factorization.

112011403433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 112011403433 its reverse (334304110211), we get a palindrome (446315513644).

The spelling of 112011403433 in words is "one hundred twelve billion, eleven million, four hundred three thousand, four hundred thirty-three".