Base | Representation |
---|---|
bin | 11001011101111111100000… |
… | …101001111010011000101001 |
3 | 112200121021010021201201001021 |
4 | 121131333200221322120221 |
5 | 104140202012111231232 |
6 | 1034121412023252441 |
7 | 32410421155465255 |
oct | 3135774051723051 |
9 | 480537107651037 |
10 | 112012221195817 |
11 | 32766130792308 |
12 | 106908762aa121 |
13 | 4a66926766137 |
14 | 1d935c594b265 |
15 | ce3a655a5397 |
hex | 65dfe0a7a629 |
112012221195817 has 2 divisors, whose sum is σ = 112012221195818. Its totient is φ = 112012221195816.
The previous prime is 112012221195773. The next prime is 112012221195883. The reversal of 112012221195817 is 718591122210211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 58410802148416 + 53601419047401 = 7642696^2 + 7321299^2 .
It is a cyclic number.
It is not a de Polignac number, because 112012221195817 - 215 = 112012221163049 is a prime.
It is not a weakly prime, because it can be changed into another prime (112012221105817) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56006110597908 + 56006110597909.
It is an arithmetic number, because the mean of its divisors is an integer number (56006110597909).
Almost surely, 2112012221195817 is an apocalyptic number.
It is an amenable number.
112012221195817 is a deficient number, since it is larger than the sum of its proper divisors (1).
112012221195817 is an equidigital number, since it uses as much as digits as its factorization.
112012221195817 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40320, while the sum is 43.
The spelling of 112012221195817 in words is "one hundred twelve trillion, twelve billion, two hundred twenty-one million, one hundred ninety-five thousand, eight hundred seventeen".
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