Base | Representation |
---|---|
bin | 10100110111010011… |
… | …00111001000001001 |
3 | 1001220122020120100022 |
4 | 22123221213020021 |
5 | 140420013424431 |
6 | 5051254550225 |
7 | 544402401041 |
oct | 123351471011 |
9 | 31818216308 |
10 | 11201311241 |
11 | 4828936a1a |
12 | 2207368375 |
13 | 1096850723 |
14 | 783914721 |
15 | 4585a707b |
hex | 29ba67209 |
11201311241 has 2 divisors, whose sum is σ = 11201311242. Its totient is φ = 11201311240.
The previous prime is 11201311139. The next prime is 11201311249. The reversal of 11201311241 is 14211310211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10947227641 + 254083600 = 104629^2 + 15940^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11201311241 is a prime.
It is not a weakly prime, because it can be changed into another prime (11201311249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5600655620 + 5600655621.
It is an arithmetic number, because the mean of its divisors is an integer number (5600655621).
Almost surely, 211201311241 is an apocalyptic number.
It is an amenable number.
11201311241 is a deficient number, since it is larger than the sum of its proper divisors (1).
11201311241 is an equidigital number, since it uses as much as digits as its factorization.
11201311241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 11201311241 its reverse (14211310211), we get a palindrome (25412621452).
The spelling of 11201311241 in words is "eleven billion, two hundred one million, three hundred eleven thousand, two hundred forty-one".
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