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11201333322132 = 22333137271333667
BaseRepresentation
bin1010001100000000001101…
…1111100110000110010100
31110122211121011211010221000
42203000003133212012110
52432010312312302012
635453453235223300
72234161324164012
oct243000337460624
943584534733830
1011201333322132
113629505707828
12130aa87a47b30
13633386a47325
142aa20c76d8b2
1514658bc01ddc
hexa30037e6194

11201333322132 has 192 divisors, whose sum is σ = 30901180334080. Its totient is φ = 3502692201600.

The previous prime is 11201333322131. The next prime is 11201333322181. The reversal of 11201333322132 is 23122333310211.

11201333322132 is a `hidden beast` number, since 1 + 1 + 2 + 0 + 1 + 333 + 322 + 1 + 3 + 2 = 666.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 11201333322096 and 11201333322105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11201333322131) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 33403563 + ... + 33737229.

Almost surely, 211201333322132 is an apocalyptic number.

11201333322132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11201333322132, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15450590167040).

11201333322132 is an abundant number, since it is smaller than the sum of its proper divisors (19699847011948).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11201333322132 is a wasteful number, since it uses less digits than its factorization.

11201333322132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 334019 (or 334011 counting only the distinct ones).

The product of its (nonzero) digits is 3888, while the sum is 27.

Adding to 11201333322132 its reverse (23122333310211), we get a palindrome (34323666632343).

It can be divided in two parts, 11201 and 333322132, that added together give a palindrome (333333333).

The spelling of 11201333322132 in words is "eleven trillion, two hundred one billion, three hundred thirty-three million, three hundred twenty-two thousand, one hundred thirty-two".