Base | Representation |
---|---|
bin | 110100001010010000… |
… | …1010111111111100010 |
3 | 101201010102001110222121 |
4 | 1220110201113333202 |
5 | 3313400420134132 |
6 | 123242552454454 |
7 | 11043540361534 |
oct | 1502441277742 |
9 | 351112043877 |
10 | 112013443042 |
11 | 43560739726 |
12 | 198610aa42a |
13 | a7416a0017 |
14 | 55c877b854 |
15 | 2da8c63497 |
hex | 1a14857fe2 |
112013443042 has 4 divisors (see below), whose sum is σ = 168020164566. Its totient is φ = 56006721520.
The previous prime is 112013443039. The next prime is 112013443093. The reversal of 112013443042 is 240344310211.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 80752020561 + 31261422481 = 284169^2 + 176809^2 .
It is a super-2 number, since 2×1120134430422 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 112013442998 and 112013443016.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28003360759 + ... + 28003360762.
Almost surely, 2112013443042 is an apocalyptic number.
112013443042 is a deficient number, since it is larger than the sum of its proper divisors (56006721524).
112013443042 is an equidigital number, since it uses as much as digits as its factorization.
112013443042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 56006721523.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 112013443042 its reverse (240344310211), we get a palindrome (352357753253).
The spelling of 112013443042 in words is "one hundred twelve billion, thirteen million, four hundred forty-three thousand, forty-two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •