1120200312113 has 2 divisors, whose sum is σ = 1120200312114. Its totient is φ = 1120200312112.

The previous prime is 1120200312079. The next prime is 1120200312137. The reversal of 1120200312113 is 3112130020211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 791053705744 + 329146606369 = 889412^2 + 573713^2 .

It is an emirp because it is prime and its reverse (3112130020211) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1120200312113 is a prime.

It is a super-2 number, since 2×1120200312113² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1120200312091 and 1120200312100.

It is not a weakly prime, because it can be changed into another prime (1120200812113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560100156056 + 560100156057.

It is an arithmetic number, because the mean of its divisors is an integer number (560100156057).

Almost surely, 2^{1120200312113} is an apocalyptic number.

It is an amenable number.

1120200312113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1120200312113 is an equidigital number, since it uses as much as digits as its factorization.

1120200312113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1120200312113 its reverse (3112130020211), we get a palindrome (4232330332324).

The spelling of 1120200312113 in words is "one trillion, one hundred twenty billion, two hundred million, three hundred twelve thousand, one hundred thirteen".