Base | Representation |
---|---|
bin | 11001011110000110110111… |
… | …100001010100010000110011 |
3 | 112200122000111211121220120002 |
4 | 121132012313201110100303 |
5 | 104140314201434330001 |
6 | 1034125155543540215 |
7 | 32411121012014165 |
oct | 3136066741242063 |
9 | 480560454556502 |
10 | 112020121011251 |
11 | 32769514a525a2 |
12 | 106922bba5a66b |
13 | 4a675b52cc73b |
14 | 1d93b34bb6935 |
15 | ce3d78db146b |
hex | 65e1b7854433 |
112020121011251 has 2 divisors, whose sum is σ = 112020121011252. Its totient is φ = 112020121011250.
The previous prime is 112020121011191. The next prime is 112020121011259. The reversal of 112020121011251 is 152110121020211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112020121011251 - 210 = 112020121010227 is a prime.
It is a super-2 number, since 2×1120201210112512 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (112020121011259) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56010060505625 + 56010060505626.
It is an arithmetic number, because the mean of its divisors is an integer number (56010060505626).
Almost surely, 2112020121011251 is an apocalyptic number.
112020121011251 is a deficient number, since it is larger than the sum of its proper divisors (1).
112020121011251 is an equidigital number, since it uses as much as digits as its factorization.
112020121011251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80, while the sum is 20.
Adding to 112020121011251 its reverse (152110121020211), we get a palindrome (264130242031462).
The spelling of 112020121011251 in words is "one hundred twelve trillion, twenty billion, one hundred twenty-one million, eleven thousand, two hundred fifty-one".
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