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112021152497 is a prime number
BaseRepresentation
bin110100001010011111…
…0110010001011110001
3101201010221120011100222
41220110332302023301
53313404403334442
6123243430022425
711043663041222
oct1502476621361
9351127504328
10112021152497
1143565024981
12198637a7a15
13a74316c127
1455c97c7249
152da97878d2
hex1a14fb22f1

112021152497 has 2 divisors, whose sum is σ = 112021152498. Its totient is φ = 112021152496.

The previous prime is 112021152457. The next prime is 112021152511. The reversal of 112021152497 is 794251120211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 94932388321 + 17088764176 = 308111^2 + 130724^2 .

It is an emirp because it is prime and its reverse (794251120211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 112021152497 - 212 = 112021148401 is a prime.

It is a super-3 number, since 3×1120211524973 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (112021152407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56010576248 + 56010576249.

It is an arithmetic number, because the mean of its divisors is an integer number (56010576249).

Almost surely, 2112021152497 is an apocalyptic number.

It is an amenable number.

112021152497 is a deficient number, since it is larger than the sum of its proper divisors (1).

112021152497 is an equidigital number, since it uses as much as digits as its factorization.

112021152497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10080, while the sum is 35.

The spelling of 112021152497 in words is "one hundred twelve billion, twenty-one million, one hundred fifty-two thousand, four hundred ninety-seven".