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112022121011081 is a prime number
BaseRepresentation
bin11001011110001000101110…
…101110101101011110001001
3112200122012200012222102112212
4121132020232232231132021
5104140332300434323311
61034130130230514505
732411221405515401
oct3136105656553611
9480565605872485
10112022121011081
113276a35099a016
1210692779805a35
134a678437769a8
141d93c84671801
15ce3e44773c8b
hex65e22ebad789

112022121011081 has 2 divisors, whose sum is σ = 112022121011082. Its totient is φ = 112022121011080.

The previous prime is 112022121011027. The next prime is 112022121011137. The reversal of 112022121011081 is 180110121220211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 106161267364681 + 5860853646400 = 10303459^2 + 2420920^2 .

It is a cyclic number.

It is not a de Polignac number, because 112022121011081 - 214 = 112022120994697 is a prime.

It is a super-3 number, since 3×1120221210110813 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (112022121016081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56011060505540 + 56011060505541.

It is an arithmetic number, because the mean of its divisors is an integer number (56011060505541).

Almost surely, 2112022121011081 is an apocalyptic number.

It is an amenable number.

112022121011081 is a deficient number, since it is larger than the sum of its proper divisors (1).

112022121011081 is an equidigital number, since it uses as much as digits as its factorization.

112022121011081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 128, while the sum is 23.

Adding to 112022121011081 its reverse (180110121220211), we get a palindrome (292132242231292).

The spelling of 112022121011081 in words is "one hundred twelve trillion, twenty-two billion, one hundred twenty-one million, eleven thousand, eighty-one".