Base | Representation |
---|---|
bin | 10000010011010011000… |
… | …110111111001010101011 |
3 | 10222002111222121222101212 |
4 | 100103103012333022223 |
5 | 121323214212234011 |
6 | 2214343355503335 |
7 | 143635266055661 |
oct | 20232306771253 |
9 | 3862458558355 |
10 | 1120233321131 |
11 | 3a20a75616a1 |
12 | 161137a57b4b |
13 | 81839905a42 |
14 | 3c310766c31 |
15 | 1e216e5908b |
hex | 104d31bf2ab |
1120233321131 has 2 divisors, whose sum is σ = 1120233321132. Its totient is φ = 1120233321130.
The previous prime is 1120233321091. The next prime is 1120233321167. The reversal of 1120233321131 is 1311233320211.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1120233321131 is a prime.
It is a super-2 number, since 2×11202333211312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1120233321097 and 1120233321106.
It is not a weakly prime, because it can be changed into another prime (1120233321191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560116660565 + 560116660566.
It is an arithmetic number, because the mean of its divisors is an integer number (560116660566).
Almost surely, 21120233321131 is an apocalyptic number.
1120233321131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1120233321131 is an equidigital number, since it uses as much as digits as its factorization.
1120233321131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 1120233321131 its reverse (1311233320211), we get a palindrome (2431466641342).
The spelling of 1120233321131 in words is "one trillion, one hundred twenty billion, two hundred thirty-three million, three hundred twenty-one thousand, one hundred thirty-one".
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