Base | Representation |
---|---|
bin | 11001011110001011101101… |
… | …100110110111101100100011 |
3 | 112200122111221101211211212111 |
4 | 121132023231212313230203 |
5 | 104140410330242412232 |
6 | 1034131420105140151 |
7 | 32411363642433163 |
oct | 3136135546675443 |
9 | 480574841754774 |
10 | 112025323404067 |
11 | 32770744627297 |
12 | 1069331218a657 |
13 | 4a67c34072798 |
14 | 1d940a9ac05a3 |
15 | ce4080996047 |
hex | 65e2ed9b7b23 |
112025323404067 has 2 divisors, whose sum is σ = 112025323404068. Its totient is φ = 112025323404066.
The previous prime is 112025323404053. The next prime is 112025323404089. The reversal of 112025323404067 is 760404323520211.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112025323404067 is a prime.
It is not a weakly prime, because it can be changed into another prime (112025323404037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56012661702033 + 56012661702034.
It is an arithmetic number, because the mean of its divisors is an integer number (56012661702034).
Almost surely, 2112025323404067 is an apocalyptic number.
112025323404067 is a deficient number, since it is larger than the sum of its proper divisors (1).
112025323404067 is an equidigital number, since it uses as much as digits as its factorization.
112025323404067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 241920, while the sum is 40.
Adding to 112025323404067 its reverse (760404323520211), we get a palindrome (872429646924278).
The spelling of 112025323404067 in words is "one hundred twelve trillion, twenty-five billion, three hundred twenty-three million, four hundred four thousand, sixty-seven".
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