Base | Representation |
---|---|
bin | 11001011110010010110111… |
… | …001111010101111011000011 |
3 | 112200200020202110222100201201 |
4 | 121132102313033111323003 |
5 | 104141022041301420342 |
6 | 1034135130015042031 |
7 | 32412055131561622 |
oct | 3136226717257303 |
9 | 480606673870651 |
10 | 112033001201347 |
11 | 32773a24535aa6 |
12 | 106948b5510317 |
13 | 4a68888912bb5 |
14 | 1d945d76756b9 |
15 | ce437ea48db7 |
hex | 65e4b73d5ec3 |
112033001201347 has 2 divisors, whose sum is σ = 112033001201348. Its totient is φ = 112033001201346.
The previous prime is 112033001201269. The next prime is 112033001201371. The reversal of 112033001201347 is 743102100330211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112033001201347 - 211 = 112033001199299 is a prime.
It is a super-2 number, since 2×1120330012013472 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (112033001201047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56016500600673 + 56016500600674.
It is an arithmetic number, because the mean of its divisors is an integer number (56016500600674).
Almost surely, 2112033001201347 is an apocalyptic number.
112033001201347 is a deficient number, since it is larger than the sum of its proper divisors (1).
112033001201347 is an equidigital number, since it uses as much as digits as its factorization.
112033001201347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 28.
Adding to 112033001201347 its reverse (743102100330211), we get a palindrome (855135101531558).
The spelling of 112033001201347 in words is "one hundred twelve trillion, thirty-three billion, one million, two hundred one thousand, three hundred forty-seven".
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