Base | Representation |
---|---|
bin | 1101010110101… |
… | …11110101100101 |
3 | 21210210212120000 |
4 | 12223113311211 |
5 | 212140030000 |
6 | 15041131513 |
7 | 2530160121 |
oct | 653276545 |
9 | 253725500 |
10 | 112033125 |
11 | 58270166 |
12 | 31629b99 |
13 | 1a2978b9 |
14 | 10c44581 |
15 | 9c80000 |
hex | 6ad7d65 |
112033125 has 50 divisors (see below), whose sum is σ = 209225214. Its totient is φ = 59724000.
The previous prime is 112033123. The next prime is 112033127. The reversal of 112033125 is 521330211.
It is an interprime number because it is at equal distance from previous prime (112033123) and next prime (112033127).
It can be written as a sum of positive squares in 5 ways, for example, as 11512449 + 100520676 = 3393^2 + 10026^2 .
It is not a de Polignac number, because 112033125 - 21 = 112033123 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 112033098 and 112033107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112033123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 49 ways as a sum of consecutive naturals, for example, 49519 + ... + 51731.
Almost surely, 2112033125 is an apocalyptic number.
112033125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
112033125 is a deficient number, since it is larger than the sum of its proper divisors (97192089).
112033125 is an frugal number, since it uses more digits than its factorization.
112033125 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2245 (or 2221 counting only the distinct ones).
The product of its (nonzero) digits is 180, while the sum is 18.
The square root of 112033125 is about 10584.5701377052. The cubic root of 112033125 is about 482.0759695571.
Adding to 112033125 its reverse (521330211), we get a palindrome (633363336).
It can be divided in two parts, 11 and 2033125, that added together give a triangular number (2033136 = T2016).
The spelling of 112033125 in words is "one hundred twelve million, thirty-three thousand, one hundred twenty-five".
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