Base | Representation |
---|---|
bin | 1010001100001111110110… |
… | …1001111000100011001111 |
3 | 1110200020102200012212222012 |
4 | 2203003331221320203033 |
5 | 2432042411230320101 |
6 | 35455425523411435 |
7 | 2234400326124413 |
oct | 243037551704317 |
9 | 43606380185865 |
10 | 11205530323151 |
11 | 363026981580a |
12 | 130b859523b7b |
13 | 6338a5412c98 |
14 | 2aa4c9d24d43 |
15 | 1467353dcbbb |
hex | a30fda788cf |
11205530323151 has 8 divisors (see below), whose sum is σ = 11293309374480. Its totient is φ = 11118057656832.
The previous prime is 11205530323111. The next prime is 11205530323153. The reversal of 11205530323151 is 15132303550211.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11205530323151 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11205530323153) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 76522820 + ... + 76669113.
It is an arithmetic number, because the mean of its divisors is an integer number (1411663671810).
Almost surely, 211205530323151 is an apocalyptic number.
11205530323151 is a deficient number, since it is larger than the sum of its proper divisors (87779051329).
11205530323151 is a wasteful number, since it uses less digits than its factorization.
11205530323151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 153192505.
The product of its (nonzero) digits is 13500, while the sum is 32.
Adding to 11205530323151 its reverse (15132303550211), we get a palindrome (26337833873362).
The spelling of 11205530323151 in words is "eleven trillion, two hundred five billion, five hundred thirty million, three hundred twenty-three thousand, one hundred fifty-one".
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