Base | Representation |
---|---|
bin | 10000010011100110001… |
… | …100010100001111010011 |
3 | 10222010100022002000000211 |
4 | 100103212030110033103 |
5 | 121324343143012032 |
6 | 2214435234024551 |
7 | 143646234320056 |
oct | 20234614241723 |
9 | 3863308060024 |
10 | 1120553485267 |
11 | 3a2251258757 |
12 | 161207118157 |
13 | 8188b043888 |
14 | 3c3410a8a9d |
15 | 1e2350ec747 |
hex | 104e63143d3 |
1120553485267 has 2 divisors, whose sum is σ = 1120553485268. Its totient is φ = 1120553485266.
The previous prime is 1120553485243. The next prime is 1120553485279. The reversal of 1120553485267 is 7625843550211.
It is a strong prime.
It is an emirp because it is prime and its reverse (7625843550211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1120553485267 - 211 = 1120553483219 is a prime.
It is a super-2 number, since 2×11205534852672 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1120553485267.
It is not a weakly prime, because it can be changed into another prime (1120553485967) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560276742633 + 560276742634.
It is an arithmetic number, because the mean of its divisors is an integer number (560276742634).
Almost surely, 21120553485267 is an apocalyptic number.
1120553485267 is a deficient number, since it is larger than the sum of its proper divisors (1).
1120553485267 is an equidigital number, since it uses as much as digits as its factorization.
1120553485267 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016000, while the sum is 49.
The spelling of 1120553485267 in words is "one trillion, one hundred twenty billion, five hundred fifty-three million, four hundred eighty-five thousand, two hundred sixty-seven".
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