Base | Representation |
---|---|
bin | 11001011111010001010111… |
… | …001111001010111001000011 |
3 | 112200220122222102001120121201 |
4 | 121133101113033022321003 |
5 | 104143122011131121123 |
6 | 1034230025110002031 |
7 | 32416652141250616 |
oct | 3137212717127103 |
9 | 480818872046551 |
10 | 112100110020163 |
11 | 3279a431731931 |
12 | 106a5904046317 |
13 | 4a71cc2086845 |
14 | 1d979622d017d |
15 | ce5eab40d5ad |
hex | 65f4573cae43 |
112100110020163 has 2 divisors, whose sum is σ = 112100110020164. Its totient is φ = 112100110020162.
The previous prime is 112100110020109. The next prime is 112100110020167. The reversal of 112100110020163 is 361020011001211.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112100110020163 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 112100110020163.
It is not a weakly prime, because it can be changed into another prime (112100110020167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56050055010081 + 56050055010082.
It is an arithmetic number, because the mean of its divisors is an integer number (56050055010082).
Almost surely, 2112100110020163 is an apocalyptic number.
112100110020163 is a deficient number, since it is larger than the sum of its proper divisors (1).
112100110020163 is an equidigital number, since it uses as much as digits as its factorization.
112100110020163 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 112100110020163 its reverse (361020011001211), we get a palindrome (473120121021374).
The spelling of 112100110020163 in words is "one hundred twelve trillion, one hundred billion, one hundred ten million, twenty thousand, one hundred sixty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •