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112100123141 = 472385109003
BaseRepresentation
bin110100001100110110…
…0000010001000000101
3101201100110011021201122
41220121230002020011
53314040112420031
6123255330403325
711045642216306
oct1503154021005
9351313137648
10112100123141
11435a5662776
1219886130545
13a75662bb16
1455d60a27ad
152db168647b
hex1a19b02205

112100123141 has 4 divisors (see below), whose sum is σ = 114485232192. Its totient is φ = 109715014092.

The previous prime is 112100123137. The next prime is 112100123153. The reversal of 112100123141 is 141321001211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 112100123141 - 22 = 112100123137 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (112100123741) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1192554455 + ... + 1192554548.

It is an arithmetic number, because the mean of its divisors is an integer number (28621308048).

Almost surely, 2112100123141 is an apocalyptic number.

It is an amenable number.

112100123141 is a deficient number, since it is larger than the sum of its proper divisors (2385109051).

112100123141 is an equidigital number, since it uses as much as digits as its factorization.

112100123141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2385109050.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 112100123141 its reverse (141321001211), we get a palindrome (253421124352).

The spelling of 112100123141 in words is "one hundred twelve billion, one hundred million, one hundred twenty-three thousand, one hundred forty-one".

Divisors: 1 47 2385109003 112100123141