Search a number
-
+
1121003011313 is a prime number
BaseRepresentation
bin10000010100000000111…
…111000111110011110001
310222011111121221021211122
4100110000333013303301
5121331303232330223
62214552012552025
7143663333243453
oct20240077076361
93864447837748
101121003011313
113a2461a80289
12161311782615
1381930205913
143c384a822d3
151e25e7e55c8
hex10500fc7cf1

1121003011313 has 2 divisors, whose sum is σ = 1121003011314. Its totient is φ = 1121003011312.

The previous prime is 1121003011309. The next prime is 1121003011361. The reversal of 1121003011313 is 3131103001211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 772723628209 + 348279383104 = 879047^2 + 590152^2 .

It is a cyclic number.

It is not a de Polignac number, because 1121003011313 - 22 = 1121003011309 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1121003011291 and 1121003011300.

It is not a weakly prime, because it can be changed into another prime (1121003013313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560501505656 + 560501505657.

It is an arithmetic number, because the mean of its divisors is an integer number (560501505657).

Almost surely, 21121003011313 is an apocalyptic number.

It is an amenable number.

1121003011313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1121003011313 is an equidigital number, since it uses as much as digits as its factorization.

1121003011313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1121003011313 its reverse (3131103001211), we get a palindrome (4252106012524).

The spelling of 1121003011313 in words is "one trillion, one hundred twenty-one billion, three million, eleven thousand, three hundred thirteen".