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11210101012057 is a prime number
BaseRepresentation
bin1010001100100000111000…
…0101101011011001011001
31110200200020012202221102111
42203020032011223121121
52432131241324341212
635501503241232321
72234621516261143
oct243101605533131
943620205687374
1011210101012057
1136321a4857a62
1213107141926a1
13634153339a2c
142aa800d91c93
151469017e0ea7
hexa320e16b659

11210101012057 has 2 divisors, whose sum is σ = 11210101012058. Its totient is φ = 11210101012056.

The previous prime is 11210101012001. The next prime is 11210101012157. The reversal of 11210101012057 is 75021010101211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9425047360576 + 1785053651481 = 3070024^2 + 1336059^2 .

It is a cyclic number.

It is not a de Polignac number, because 11210101012057 - 215 = 11210100979289 is a prime.

It is a super-3 number, since 3×112101010120573 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (11210101012157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605050506028 + 5605050506029.

It is an arithmetic number, because the mean of its divisors is an integer number (5605050506029).

Almost surely, 211210101012057 is an apocalyptic number.

It is an amenable number.

11210101012057 is a deficient number, since it is larger than the sum of its proper divisors (1).

11210101012057 is an equidigital number, since it uses as much as digits as its factorization.

11210101012057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 140, while the sum is 22.

Adding to 11210101012057 its reverse (75021010101211), we get a palindrome (86231111113268).

The spelling of 11210101012057 in words is "eleven trillion, two hundred ten billion, one hundred one million, twelve thousand, fifty-seven".