Base | Representation |
---|---|
bin | 11001011111010011000111… |
… | …111001010101000010010001 |
3 | 112200220211212010121121002122 |
4 | 121133103013321111002101 |
5 | 104143134344012314303 |
6 | 1034230540425224025 |
7 | 32420050031654624 |
oct | 3137230771250221 |
9 | 480824763547078 |
10 | 112102000119953 |
11 | 327a0211635878 |
12 | 106a6151032015 |
13 | 4a7223383209c |
14 | 1d97aa133bdbb |
15 | ce606c312e38 |
hex | 65f4c7e55091 |
112102000119953 has 2 divisors, whose sum is σ = 112102000119954. Its totient is φ = 112102000119952.
The previous prime is 112102000119937. The next prime is 112102000119959. The reversal of 112102000119953 is 359911000201211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 88401139187344 + 23700860932609 = 9402188^2 + 4868353^2 .
It is an emirp because it is prime and its reverse (359911000201211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 112102000119953 - 24 = 112102000119937 is a prime.
It is not a weakly prime, because it can be changed into another prime (112102000119959) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56051000059976 + 56051000059977.
It is an arithmetic number, because the mean of its divisors is an integer number (56051000059977).
Almost surely, 2112102000119953 is an apocalyptic number.
It is an amenable number.
112102000119953 is a deficient number, since it is larger than the sum of its proper divisors (1).
112102000119953 is an equidigital number, since it uses as much as digits as its factorization.
112102000119953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4860, while the sum is 35.
The spelling of 112102000119953 in words is "one hundred twelve trillion, one hundred two billion, one hundred nineteen thousand, nine hundred fifty-three".
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