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112102000119953 is a prime number
BaseRepresentation
bin11001011111010011000111…
…111001010101000010010001
3112200220211212010121121002122
4121133103013321111002101
5104143134344012314303
61034230540425224025
732420050031654624
oct3137230771250221
9480824763547078
10112102000119953
11327a0211635878
12106a6151032015
134a7223383209c
141d97aa133bdbb
15ce606c312e38
hex65f4c7e55091

112102000119953 has 2 divisors, whose sum is σ = 112102000119954. Its totient is φ = 112102000119952.

The previous prime is 112102000119937. The next prime is 112102000119959. The reversal of 112102000119953 is 359911000201211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 88401139187344 + 23700860932609 = 9402188^2 + 4868353^2 .

It is an emirp because it is prime and its reverse (359911000201211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 112102000119953 - 24 = 112102000119937 is a prime.

It is not a weakly prime, because it can be changed into another prime (112102000119959) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56051000059976 + 56051000059977.

It is an arithmetic number, because the mean of its divisors is an integer number (56051000059977).

Almost surely, 2112102000119953 is an apocalyptic number.

It is an amenable number.

112102000119953 is a deficient number, since it is larger than the sum of its proper divisors (1).

112102000119953 is an equidigital number, since it uses as much as digits as its factorization.

112102000119953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4860, while the sum is 35.

The spelling of 112102000119953 in words is "one hundred twelve trillion, one hundred two billion, one hundred nineteen thousand, nine hundred fifty-three".