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11210201211000 = 23353112123125087
BaseRepresentation
bin1010001100100001010000…
…0011111010000001111000
31110200200111012022120112110
42203020110003322001320
52432131443002223000
635501521221012320
72234624144042301
oct243102403720170
943620435276473
1011210201211000
113632246374a00
1213107418540a0
1363416b01cc4c
142aa8103d57a8
1514690a4d4850
hexa32140fa078

11210201211000 has 384 divisors, whose sum is σ = 38477268910080. Its totient is φ = 2715308640000.

The previous prime is 11210201210891. The next prime is 11210201211031. The reversal of 11210201211000 is 11210201211.

It is a super-2 number, since 2×112102012110002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 446840457 + ... + 446865543.

It is an arithmetic number, because the mean of its divisors is an integer number (100201221120).

Almost surely, 211210201211000 is an apocalyptic number.

11210201211000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11210201211000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19238634455040).

11210201211000 is an abundant number, since it is smaller than the sum of its proper divisors (27267067699080).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11210201211000 is a wasteful number, since it uses less digits than its factorization.

11210201211000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26364 (or 26339 counting only the distinct ones).

The product of its (nonzero) digits is 8, while the sum is 12.

Adding to 11210201211000 its reverse (11210201211), we get a palindrome (11221411412211).

11210201211000 divided by its reverse (11210201211) gives a cube (1000 = 103).

The spelling of 11210201211000 in words is "eleven trillion, two hundred ten billion, two hundred one million, two hundred eleven thousand".