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112102021001147 is a prime number
BaseRepresentation
bin11001011111010011001001…
…001000111110111110111011
3112200220211220120220110201012
4121133103021020332332323
5104143134414334014042
61034230542452544135
732420050404314012
oct3137231110767673
9480824816813635
10112102021001147
11327a02223a8161
12106a615802204b
134a72237c63618
141d97aa4015a79
15ce606e089e82
hex65f4c923efbb

112102021001147 has 2 divisors, whose sum is σ = 112102021001148. Its totient is φ = 112102021001146.

The previous prime is 112102021001021. The next prime is 112102021001153. The reversal of 112102021001147 is 741100120201211.

It is a strong prime.

It is an emirp because it is prime and its reverse (741100120201211) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-112102021001147 is a prime.

It is a super-2 number, since 2×1121020210011472 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (112102021001647) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56051010500573 + 56051010500574.

It is an arithmetic number, because the mean of its divisors is an integer number (56051010500574).

Almost surely, 2112102021001147 is an apocalyptic number.

112102021001147 is a deficient number, since it is larger than the sum of its proper divisors (1).

112102021001147 is an equidigital number, since it uses as much as digits as its factorization.

112102021001147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 224, while the sum is 23.

Adding to 112102021001147 its reverse (741100120201211), we get a palindrome (853202141202358).

The spelling of 112102021001147 in words is "one hundred twelve trillion, one hundred two billion, twenty-one million, one thousand, one hundred forty-seven".