Base | Representation |
---|---|
bin | 1010001100100001010010… |
… | …1101011100011111110011 |
3 | 1110200200111221210210112211 |
4 | 2203020110231130133303 |
5 | 2432132003244200313 |
6 | 35501522250232551 |
7 | 2234624335434013 |
oct | 243102455343763 |
9 | 43620457723484 |
10 | 11210212100083 |
11 | 3632251532047 |
12 | 1310745425757 |
13 | 6341703633a9 |
14 | 2aa811a2bc43 |
15 | 14690b435e3d |
hex | a3214b5c7f3 |
11210212100083 has 2 divisors, whose sum is σ = 11210212100084. Its totient is φ = 11210212100082.
The previous prime is 11210212100051. The next prime is 11210212100107. The reversal of 11210212100083 is 38000121201211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11210212100083 - 25 = 11210212100051 is a prime.
It is not a weakly prime, because it can be changed into another prime (11210212100023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605106050041 + 5605106050042.
It is an arithmetic number, because the mean of its divisors is an integer number (5605106050042).
Almost surely, 211210212100083 is an apocalyptic number.
11210212100083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11210212100083 is an equidigital number, since it uses as much as digits as its factorization.
11210212100083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 22.
Adding to 11210212100083 its reverse (38000121201211), we get a palindrome (49210333301294).
The spelling of 11210212100083 in words is "eleven trillion, two hundred ten billion, two hundred twelve million, one hundred thousand, eighty-three".
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