Base | Representation |
---|---|
bin | 11001011111010011001111… |
… | …001011000100001011001001 |
3 | 112200220212011122100102010222 |
4 | 121133103033023010023021 |
5 | 104143140121241204433 |
6 | 1034231000510115425 |
7 | 32420053043502356 |
oct | 3137231713041311 |
9 | 480825148312128 |
10 | 112102122209993 |
11 | 327a0274544933 |
12 | 106a6185aabb75 |
13 | 4a72252c0b406 |
14 | 1d97ab363d62d |
15 | ce6077dccb98 |
hex | 65f4cf2c42c9 |
112102122209993 has 2 divisors, whose sum is σ = 112102122209994. Its totient is φ = 112102122209992.
The previous prime is 112102122209983. The next prime is 112102122210047. The reversal of 112102122209993 is 399902221201211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 90594760624384 + 21507361585609 = 9518128^2 + 4637603^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112102122209993 is a prime.
It is not a weakly prime, because it can be changed into another prime (112102122209983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56051061104996 + 56051061104997.
It is an arithmetic number, because the mean of its divisors is an integer number (56051061104997).
Almost surely, 2112102122209993 is an apocalyptic number.
It is an amenable number.
112102122209993 is a deficient number, since it is larger than the sum of its proper divisors (1).
112102122209993 is an equidigital number, since it uses as much as digits as its factorization.
112102122209993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69984, while the sum is 44.
The spelling of 112102122209993 in words is "one hundred twelve trillion, one hundred two billion, one hundred twenty-two million, two hundred nine thousand, nine hundred ninety-three".
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