1121021300101 has 4 divisors (see below), whose sum is σ = 1121519312704. Its totient is φ = 1120523287500.

The previous prime is 1121021300053. The next prime is 1121021300131. The reversal of 1121021300101 is 1010031201211.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1121021300101 - 2³⁹ = 571265486213 is a prime.

It is a super-2 number, since 2×1121021300101² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1121021300131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 249002925 + ... + 249007426.

It is an arithmetic number, because the mean of its divisors is an integer number (280379828176).

Almost surely, 2^{1121021300101} is an apocalyptic number.

It is an amenable number.

1121021300101 is a deficient number, since it is larger than the sum of its proper divisors (498012603).

1121021300101 is an equidigital number, since it uses as much as digits as its factorization.

1121021300101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 498012602.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 1121021300101 its reverse (1010031201211), we get a palindrome (2131052501312).

The spelling of 1121021300101 in words is "one trillion, one hundred twenty-one billion, twenty-one million, three hundred thousand, one hundred one".