Base | Representation |
---|---|
bin | 10000010100000010101… |
… | …011011101010111000101 |
3 | 10222011120121101011002010 |
4 | 100110002223131113011 |
5 | 121331333020124031 |
6 | 2214554505404433 |
7 | 143664126526005 |
oct | 20240253352705 |
9 | 3864517334063 |
10 | 1121031411141 |
11 | 3a2477008514 |
12 | 16131b199719 |
13 | 8193606a455 |
14 | 3c388756005 |
15 | 1e262055246 |
hex | 10502add5c5 |
1121031411141 has 8 divisors (see below), whose sum is σ = 1507936057920. Its totient is φ = 740740519232.
The previous prime is 1121031411121. The next prime is 1121031411173. The reversal of 1121031411141 is 1411141301211.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1121031411141 - 210 = 1121031410117 is a prime.
It is a super-2 number, since 2×11210314111412 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1121031411121) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1653438321 + ... + 1653438998.
It is an arithmetic number, because the mean of its divisors is an integer number (188492007240).
Almost surely, 21121031411141 is an apocalyptic number.
It is an amenable number.
1121031411141 is a deficient number, since it is larger than the sum of its proper divisors (386904646779).
1121031411141 is a wasteful number, since it uses less digits than its factorization.
1121031411141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3306877435.
The product of its (nonzero) digits is 96, while the sum is 21.
Adding to 1121031411141 its reverse (1411141301211), we get a palindrome (2532172712352).
The spelling of 1121031411141 in words is "one trillion, one hundred twenty-one billion, thirty-one million, four hundred eleven thousand, one hundred forty-one".
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