Base | Representation |
---|---|
bin | 110100001100111011… |
… | …1100110010111000111 |
3 | 101201100122212022212000 |
4 | 1220121313212113013 |
5 | 3314041401431033 |
6 | 123255515400343 |
7 | 11046010045050 |
oct | 1503167462707 |
9 | 351318768760 |
10 | 112103155143 |
11 | 435a7343761 |
12 | 198871530b3 |
13 | a757150bc5 |
14 | 55d6651727 |
15 | 2db1a84a13 |
hex | 1a19de65c7 |
112103155143 has 64 divisors (see below), whose sum is σ = 194543616000. Its totient is φ = 62476559712.
The previous prime is 112103155123. The next prime is 112103155193. The reversal of 112103155143 is 341551301211.
112103155143 is a `hidden beast` number, since 1 + 1 + 2 + 103 + 1 + 551 + 4 + 3 = 666.
It is not a de Polignac number, because 112103155143 - 217 = 112103024071 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112103155123) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1376598 + ... + 1455756.
It is an arithmetic number, because the mean of its divisors is an integer number (3039744000).
Almost surely, 2112103155143 is an apocalyptic number.
112103155143 is a deficient number, since it is larger than the sum of its proper divisors (82440460857).
112103155143 is a wasteful number, since it uses less digits than its factorization.
112103155143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 79361 (or 79355 counting only the distinct ones).
The product of its (nonzero) digits is 1800, while the sum is 27.
Adding to 112103155143 its reverse (341551301211), we get a palindrome (453654456354).
The spelling of 112103155143 in words is "one hundred twelve billion, one hundred three million, one hundred fifty-five thousand, one hundred forty-three".
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