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11210322113 is a prime number
BaseRepresentation
bin10100111000010111…
…11111000011000001
31001221021012100221022
422130023333003001
5140424320301423
65052220035225
7544542110564
oct123413770301
931837170838
1011210322113
114832a30a21
12220a392b15
131098686cc3
14784bbc4db
15459286dc8
hex29c2ff0c1

11210322113 has 2 divisors, whose sum is σ = 11210322114. Its totient is φ = 11210322112.

The previous prime is 11210322091. The next prime is 11210322127. The reversal of 11210322113 is 31122301211.

11210322113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8996901904 + 2213420209 = 94852^2 + 47047^2 .

It is a cyclic number.

It is not a de Polignac number, because 11210322113 - 222 = 11206127809 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11210322091 and 11210322100.

It is not a weakly prime, because it can be changed into another prime (11210328113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605161056 + 5605161057.

It is an arithmetic number, because the mean of its divisors is an integer number (5605161057).

Almost surely, 211210322113 is an apocalyptic number.

It is an amenable number.

11210322113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11210322113 is an equidigital number, since it uses as much as digits as its factorization.

11210322113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 11210322113 its reverse (31122301211), we get a palindrome (42332623324).

The spelling of 11210322113 in words is "eleven billion, two hundred ten million, three hundred twenty-two thousand, one hundred thirteen".