Base | Representation |
---|---|
bin | 1010001100100010000111… |
… | …1000010001111110110001 |
3 | 1110200201002100112221011201 |
4 | 2203020201320101332301 |
5 | 2432132431324410101 |
6 | 35502000222011201 |
7 | 2234632660432363 |
oct | 243104170217661 |
9 | 43621070487151 |
10 | 11210433044401 |
11 | 363235521a858 |
12 | 13107a7416b01 |
13 | 6341a7071886 |
14 | 2aa833102d33 |
15 | 146920a2ae01 |
hex | a3221e11fb1 |
11210433044401 has 2 divisors, whose sum is σ = 11210433044402. Its totient is φ = 11210433044400.
The previous prime is 11210433044357. The next prime is 11210433044467. The reversal of 11210433044401 is 10444033401211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8895896794801 + 2314536249600 = 2982599^2 + 1521360^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11210433044401 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11210433044401.
It is not a weakly prime, because it can be changed into another prime (11210433044101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605216522200 + 5605216522201.
It is an arithmetic number, because the mean of its divisors is an integer number (5605216522201).
Almost surely, 211210433044401 is an apocalyptic number.
It is an amenable number.
11210433044401 is a deficient number, since it is larger than the sum of its proper divisors (1).
11210433044401 is an equidigital number, since it uses as much as digits as its factorization.
11210433044401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 11210433044401 its reverse (10444033401211), we get a palindrome (21654466445612).
The spelling of 11210433044401 in words is "eleven trillion, two hundred ten billion, four hundred thirty-three million, forty-four thousand, four hundred one".
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