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112105133503 = 1134729369959
BaseRepresentation
bin110100001100111111…
…1001001010110111111
3101201100210120211122121
41220121333021112333
53314042403233003
6123300030023411
711046032624626
oct1503177112677
9351323524577
10112105133503
11435a8475070
1219887947b67
13a75769452c
1455d6a086bd
152db1d25cbd
hex1a19fc95bf

112105133503 has 8 divisors (see below), whose sum is σ = 122648952960. Its totient is φ = 101620054680.

The previous prime is 112105133479. The next prime is 112105133507. The reversal of 112105133503 is 305331501211.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 112105133503 - 213 = 112105125311 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (112105133507) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14681163 + ... + 14688796.

It is an arithmetic number, because the mean of its divisors is an integer number (15331119120).

Almost surely, 2112105133503 is an apocalyptic number.

112105133503 is a deficient number, since it is larger than the sum of its proper divisors (10543819457).

112105133503 is a wasteful number, since it uses less digits than its factorization.

112105133503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29370317.

The product of its (nonzero) digits is 1350, while the sum is 25.

Adding to 112105133503 its reverse (305331501211), we get a palindrome (417436634714).

The spelling of 112105133503 in words is "one hundred twelve billion, one hundred five million, one hundred thirty-three thousand, five hundred three".

Divisors: 1 11 347 3817 29369959 323069549 10191375773 112105133503