Base | Representation |
---|---|
bin | 11001011111011010101010… |
… | …101010111101101111101011 |
3 | 112200221121202121111102112202 |
4 | 121133122222222331233223 |
5 | 104143302441013443432 |
6 | 1034234400244330415 |
7 | 32420454532456202 |
oct | 3137325252755753 |
9 | 480847677442482 |
10 | 112110099749867 |
11 | 327a369867169a |
12 | 106a78316a3a0b |
13 | 4a72c248b93cb |
14 | 1d9822cd3c239 |
15 | ce639343d462 |
hex | 65f6aaabdbeb |
112110099749867 has 2 divisors, whose sum is σ = 112110099749868. Its totient is φ = 112110099749866.
The previous prime is 112110099749783. The next prime is 112110099749899. The reversal of 112110099749867 is 768947990011211.
It is a strong prime.
It is an emirp because it is prime and its reverse (768947990011211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 112110099749867 - 218 = 112110099487723 is a prime.
It is not a weakly prime, because it can be changed into another prime (112110099745867) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56055049874933 + 56055049874934.
It is an arithmetic number, because the mean of its divisors is an integer number (56055049874934).
Almost surely, 2112110099749867 is an apocalyptic number.
112110099749867 is a deficient number, since it is larger than the sum of its proper divisors (1).
112110099749867 is an equidigital number, since it uses as much as digits as its factorization.
112110099749867 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13716864, while the sum is 65.
The spelling of 112110099749867 in words is "one hundred twelve trillion, one hundred ten billion, ninety-nine million, seven hundred forty-nine thousand, eight hundred sixty-seven".
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