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11211011221121 is a prime number
BaseRepresentation
bin1010001100100100010001…
…0101110110011010000001
31110200202120122111100112022
42203021010111312122001
52432140122333033441
635502133434211225
72234653211026655
oct243110425663201
943622518440468
1011211011221121
113632621622558
121310928b83b15
13634269a9918a
142aa889c08a65
1514695668784b
hexa3244576681

11211011221121 has 2 divisors, whose sum is σ = 11211011221122. Its totient is φ = 11211011221120.

The previous prime is 11211011221019. The next prime is 11211011221169. The reversal of 11211011221121 is 12112211011211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9009986768896 + 2201024452225 = 3001664^2 + 1483585^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11211011221121 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 11211011221121.

It is not a weakly prime, because it can be changed into another prime (11211011271121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605505610560 + 5605505610561.

It is an arithmetic number, because the mean of its divisors is an integer number (5605505610561).

Almost surely, 211211011221121 is an apocalyptic number.

It is an amenable number.

11211011221121 is a deficient number, since it is larger than the sum of its proper divisors (1).

11211011221121 is an equidigital number, since it uses as much as digits as its factorization.

11211011221121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16, while the sum is 17.

Adding to 11211011221121 its reverse (12112211011211), we get a palindrome (23323222232332).

The spelling of 11211011221121 in words is "eleven trillion, two hundred eleven billion, eleven million, two hundred twenty-one thousand, one hundred twenty-one".