Base | Representation |
---|---|
bin | 11001011111011011100110… |
… | …111001001011101100111011 |
3 | 112200221201101000200001002211 |
4 | 121133123212321023230323 |
5 | 104143312023142010021 |
6 | 1034235044420035551 |
7 | 32420521551416455 |
oct | 3137334671135473 |
9 | 480851330601084 |
10 | 112111110110011 |
11 | 327a4066a21181 |
12 | 106a7a73b32bb7 |
13 | 4a7305601304c |
14 | 1d982c71c52d5 |
15 | ce6401eb93e1 |
hex | 65f6e6e4bb3b |
112111110110011 has 2 divisors, whose sum is σ = 112111110110012. Its totient is φ = 112111110110010.
The previous prime is 112111110109979. The next prime is 112111110110023. The reversal of 112111110110011 is 110011011111211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112111110110011 - 25 = 112111110109979 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 112111110109973 and 112111110110000.
It is not a weakly prime, because it can be changed into another prime (112111110113011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56055555055005 + 56055555055006.
It is an arithmetic number, because the mean of its divisors is an integer number (56055555055006).
Almost surely, 2112111110110011 is an apocalyptic number.
112111110110011 is a deficient number, since it is larger than the sum of its proper divisors (1).
112111110110011 is an equidigital number, since it uses as much as digits as its factorization.
112111110110011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2, while the sum is 13.
Adding to 112111110110011 its reverse (110011011111211), we get a palindrome (222122121221222).
The spelling of 112111110110011 in words is "one hundred twelve trillion, one hundred eleven billion, one hundred ten million, one hundred ten thousand, eleven".
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