Base | Representation |
---|---|
bin | 10000010100000111011… |
… | …110111000111001100011 |
3 | 10222011210020000121011012 |
4 | 100110013132320321203 |
5 | 121332014133032042 |
6 | 2215010505011135 |
7 | 143666125533134 |
oct | 20240736707143 |
9 | 3864706017135 |
10 | 1121112002147 |
11 | 3a2508552755 |
12 | 161342183aab |
13 | 81949976837 |
14 | 3c395333c8b |
15 | 1e269173e82 |
hex | 105077b8e63 |
1121112002147 has 2 divisors, whose sum is σ = 1121112002148. Its totient is φ = 1121112002146.
The previous prime is 1121112002111. The next prime is 1121112002159. The reversal of 1121112002147 is 7412002111211.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1121112002147 is a prime.
It is not a weakly prime, because it can be changed into another prime (1121112002167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560556001073 + 560556001074.
It is an arithmetic number, because the mean of its divisors is an integer number (560556001074).
Almost surely, 21121112002147 is an apocalyptic number.
1121112002147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121112002147 is an equidigital number, since it uses as much as digits as its factorization.
1121112002147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224, while the sum is 23.
Adding to 1121112002147 its reverse (7412002111211), we get a palindrome (8533114113358).
The spelling of 1121112002147 in words is "one trillion, one hundred twenty-one billion, one hundred twelve million, two thousand, one hundred forty-seven".
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