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11211121123102 = 25605560561551
BaseRepresentation
bin1010001100100100101011…
…1001000101111100011110
31110200202212022021221201001
42203021022321011330132
52432140334001414402
635502152401540514
72234656014132625
oct243111271057436
943622768257631
1011211121123102
11363267866753a
12131095994473a
13634286798a34
142aa89a6566bc
15146961146187
hexa324ae45f1e

11211121123102 has 4 divisors (see below), whose sum is σ = 16816681684656. Its totient is φ = 5605560561550.

The previous prime is 11211121123073. The next prime is 11211121123127. The reversal of 11211121123102 is 20132112111211.

11211121123102 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a self number, because there is not a number n which added to its sum of digits gives 11211121123102.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2802780280774 + ... + 2802780280777.

It is an arithmetic number, because the mean of its divisors is an integer number (4204170421164).

Almost surely, 211211121123102 is an apocalyptic number.

11211121123102 is a deficient number, since it is larger than the sum of its proper divisors (5605560561554).

11211121123102 is an equidigital number, since it uses as much as digits as its factorization.

11211121123102 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5605560561553.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 11211121123102 its reverse (20132112111211), we get a palindrome (31343233234313).

The spelling of 11211121123102 in words is "eleven trillion, two hundred eleven billion, one hundred twenty-one million, one hundred twenty-three thousand, one hundred two".

Divisors: 1 2 5605560561551 11211121123102