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11211140243 is a prime number
BaseRepresentation
bin10100111000011110…
…00110110010010011
31001221022201221012102
422130033012302103
5140430022441433
65052245351015
7544552056032
oct123417066223
931838657172
1011211140243
11483343a666
12220a70846b
1310988b24c4
14784d52719
154593994e8
hex29c3c6c93

11211140243 has 2 divisors, whose sum is σ = 11211140244. Its totient is φ = 11211140242.

The previous prime is 11211140233. The next prime is 11211140261. The reversal of 11211140243 is 34204111211.

11211140243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (34204111211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11211140243 - 224 = 11194363027 is a prime.

It is not a weakly prime, because it can be changed into another prime (11211140203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605570121 + 5605570122.

It is an arithmetic number, because the mean of its divisors is an integer number (5605570122).

Almost surely, 211211140243 is an apocalyptic number.

11211140243 is a deficient number, since it is larger than the sum of its proper divisors (1).

11211140243 is an equidigital number, since it uses as much as digits as its factorization.

11211140243 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 11211140243 its reverse (34204111211), we get a palindrome (45415251454).

The spelling of 11211140243 in words is "eleven billion, two hundred eleven million, one hundred forty thousand, two hundred forty-three".