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11211200012122 = 211509600000551
BaseRepresentation
bin1010001100100100111110…
…0110000001111101011010
31110200210001210201221002121
42203021033212001331122
52432141014200341442
635502204300451454
72234660662521025
oct243111746017532
943623053657077
1011211200012122
113632709149a80
121310980249b8a
13634299c2a526
142aa8a6d101bc
1514696802a967
hexa324f981f5a

11211200012122 has 8 divisors (see below), whose sum is σ = 18345600019872. Its totient is φ = 5096000005500.

The previous prime is 11211200012119. The next prime is 11211200012141. The reversal of 11211200012122 is 22121000211211.

11211200012122 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 11211200012096 and 11211200012105.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 254800000254 + ... + 254800000297.

It is an arithmetic number, because the mean of its divisors is an integer number (2293200002484).

Almost surely, 211211200012122 is an apocalyptic number.

11211200012122 is a deficient number, since it is larger than the sum of its proper divisors (7134400007750).

11211200012122 is a wasteful number, since it uses less digits than its factorization.

11211200012122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 509600000564.

The product of its (nonzero) digits is 32, while the sum is 16.

Adding to 11211200012122 its reverse (22121000211211), we get a palindrome (33332200223333).

The spelling of 11211200012122 in words is "eleven trillion, two hundred eleven billion, two hundred million, twelve thousand, one hundred twenty-two".

Divisors: 1 2 11 22 509600000551 1019200001102 5605600006061 11211200012122