Base | Representation |
---|---|
bin | 11001011111011100011011… |
… | …111100010011110011000011 |
3 | 112200221210200001101100002201 |
4 | 121133130123330103303003 |
5 | 104143320334012401201 |
6 | 1034235313012054031 |
7 | 32420552606405656 |
oct | 3137343374236303 |
9 | 480853601340081 |
10 | 112112000122051 |
11 | 327a4483351416 |
12 | 106a8082004317 |
13 | 4a731685204a7 |
14 | 1d9836d4a189d |
15 | ce64551c1801 |
hex | 65f71bf13cc3 |
112112000122051 has 2 divisors, whose sum is σ = 112112000122052. Its totient is φ = 112112000122050.
The previous prime is 112112000122043. The next prime is 112112000122127. The reversal of 112112000122051 is 150221000211211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112112000122051 - 23 = 112112000122043 is a prime.
It is not a weakly prime, because it can be changed into another prime (112112000122351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56056000061025 + 56056000061026.
It is an arithmetic number, because the mean of its divisors is an integer number (56056000061026).
Almost surely, 2112112000122051 is an apocalyptic number.
112112000122051 is a deficient number, since it is larger than the sum of its proper divisors (1).
112112000122051 is an equidigital number, since it uses as much as digits as its factorization.
112112000122051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 19.
Adding to 112112000122051 its reverse (150221000211211), we get a palindrome (262333000333262).
The spelling of 112112000122051 in words is "one hundred twelve trillion, one hundred twelve billion, one hundred twenty-two thousand, fifty-one".
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