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1121120133300 = 22365220697433
BaseRepresentation
bin10000010100000111111…
…101111010000010110100
310222011210210022201000000
4100110013331322002310
5121332023223231200
62215011355151300
7143666254620126
oct20240775720264
93864723281000
101121120133300
113a25120a6812
12161344a45530
138194b56287b
143c39644d216
151e269c2d300
hex10507f7a0b4

1121120133300 has 252 divisors, whose sum is σ = 3649831356780. Its totient is φ = 298780669440.

The previous prime is 1121120133253. The next prime is 1121120133307. The reversal of 1121120133300 is 33310211211.

1121120133300 is a `hidden beast` number, since 1 + 1 + 211 + 20 + 133 + 300 = 666.

It can be written as a sum of positive squares in 6 ways, for example, as 357922206756 + 763197926544 = 598266^2 + 873612^2 .

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1121120133307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 83 ways as a sum of consecutive naturals, for example, 150826384 + ... + 150833816.

It is an arithmetic number, because the mean of its divisors is an integer number (14483457765).

Almost surely, 21121120133300 is an apocalyptic number.

1121120133300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1121120133300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1824915678390).

1121120133300 is an abundant number, since it is smaller than the sum of its proper divisors (2528711223480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1121120133300 is a wasteful number, since it uses less digits than its factorization.

1121120133300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9534 (or 9512 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 1121120133300 its reverse (33310211211), we get a palindrome (1154430344511).

The spelling of 1121120133300 in words is "one trillion, one hundred twenty-one billion, one hundred twenty million, one hundred thirty-three thousand, three hundred".