Base | Representation |
---|---|
bin | 11001011111011100100010… |
… | …100111011110111100011001 |
3 | 112200221210221212002120100102 |
4 | 121133130202213132330121 |
5 | 104143321101144300233 |
6 | 1034235332052145145 |
7 | 32420555436261416 |
oct | 3137344247367431 |
9 | 480853855076312 |
10 | 112112112103193 |
11 | 327a4530586514 |
12 | 106a80b36081b5 |
13 | 4a7318579a517 |
14 | 1d983802d110d |
15 | ce645ee411e8 |
hex | 65f7229def19 |
112112112103193 has 2 divisors, whose sum is σ = 112112112103194. Its totient is φ = 112112112103192.
The previous prime is 112112112103181. The next prime is 112112112103231. The reversal of 112112112103193 is 391301211211211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 111680256780544 + 431855322649 = 10567888^2 + 657157^2 .
It is a cyclic number.
It is not a de Polignac number, because 112112112103193 - 28 = 112112112102937 is a prime.
It is not a weakly prime, because it can be changed into another prime (112112112163193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56056056051596 + 56056056051597.
It is an arithmetic number, because the mean of its divisors is an integer number (56056056051597).
Almost surely, 2112112112103193 is an apocalyptic number.
It is an amenable number.
112112112103193 is a deficient number, since it is larger than the sum of its proper divisors (1).
112112112103193 is an equidigital number, since it uses as much as digits as its factorization.
112112112103193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 29.
The spelling of 112112112103193 in words is "one hundred twelve trillion, one hundred twelve billion, one hundred twelve million, one hundred three thousand, one hundred ninety-three".
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