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112112123113 is a prime number
BaseRepresentation
bin110100001101001100…
…1110011110011101001
3101201101021201221121001
41220122121303303221
53314101200414423
6123300435515001
711046146215534
oct1503231636351
9351337657531
10112112123113
1143601409501
121988a158a61
13a758c70ab3
1455d7907a1b
152db2756cad
hex1a1a673ce9

112112123113 has 2 divisors, whose sum is σ = 112112123114. Its totient is φ = 112112123112.

The previous prime is 112112123099. The next prime is 112112123147. The reversal of 112112123113 is 311321211211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 71611365609 + 40500757504 = 267603^2 + 201248^2 .

It is an emirp because it is prime and its reverse (311321211211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 112112123113 - 29 = 112112122601 is a prime.

It is not a weakly prime, because it can be changed into another prime (112112129113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56056061556 + 56056061557.

It is an arithmetic number, because the mean of its divisors is an integer number (56056061557).

Almost surely, 2112112123113 is an apocalyptic number.

It is an amenable number.

112112123113 is a deficient number, since it is larger than the sum of its proper divisors (1).

112112123113 is an equidigital number, since it uses as much as digits as its factorization.

112112123113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 72, while the sum is 19.

Adding to 112112123113 its reverse (311321211211), we get a palindrome (423433334324).

It can be divided in two parts, 112112 and 123113, that added together give a square (235225 = 4852).

The spelling of 112112123113 in words is "one hundred twelve billion, one hundred twelve million, one hundred twenty-three thousand, one hundred thirteen".