Base | Representation |
---|---|
bin | 11001011111011101011110… |
… | …110000100111101011001100 |
3 | 112200221220120011202111120112 |
4 | 121133131132300213223030 |
5 | 104143330133002144322 |
6 | 1034240020135135152 |
7 | 32420622441003155 |
oct | 3137353660475314 |
9 | 480856504674515 |
10 | 112113121131212 |
11 | 327a49a9106173 |
12 | 106a83355144b8 |
13 | 4a732b6848a16 |
14 | 1d9843830c92c |
15 | ce64bd8075e2 |
hex | 65f75ec27acc |
112113121131212 has 24 divisors (see below), whose sum is σ = 204737499542016. Its totient is φ = 53616911533328.
The previous prime is 112113121131203. The next prime is 112113121131241. The reversal of 112113121131212 is 212131121311211.
It is a super-3 number, since 3×1121131211312123 (a number of 43 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (23).
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25294148 + ... + 29394219.
It is an arithmetic number, because the mean of its divisors is an integer number (8530729147584).
Almost surely, 2112113121131212 is an apocalyptic number.
It is an amenable number.
112113121131212 is a deficient number, since it is larger than the sum of its proper divisors (92624378410804).
112113121131212 is a wasteful number, since it uses less digits than its factorization.
112113121131212 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54710677 (or 54710675 counting only the distinct ones).
The product of its digits is 144, while the sum is 23.
Adding to 112113121131212 its reverse (212131121311211), we get a palindrome (324244242442423).
The spelling of 112113121131212 in words is "one hundred twelve trillion, one hundred thirteen billion, one hundred twenty-one million, one hundred thirty-one thousand, two hundred twelve".
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