Base | Representation |
---|---|
bin | 10000010100001000101… |
… | …000001111001101100001 |
3 | 10222011211120012110212201 |
4 | 100110020220033031201 |
5 | 121332034043330144 |
6 | 2215012433053201 |
7 | 143666451135145 |
oct | 20241050171541 |
9 | 3864746173781 |
10 | 1121131230049 |
11 | 3a2518395986 |
12 | 1613486b7201 |
13 | 819509496ac |
14 | 3c397adb225 |
15 | 1e26abc11d4 |
hex | 10508a0f361 |
1121131230049 has 2 divisors, whose sum is σ = 1121131230050. Its totient is φ = 1121131230048.
The previous prime is 1121131229989. The next prime is 1121131230061. The reversal of 1121131230049 is 9400321311211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1105137075025 + 15994155024 = 1051255^2 + 126468^2 .
It is a cyclic number.
It is not a de Polignac number, because 1121131230049 - 213 = 1121131221857 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1121131229999 and 1121131230026.
It is not a weakly prime, because it can be changed into another prime (1121131230649) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560565615024 + 560565615025.
It is an arithmetic number, because the mean of its divisors is an integer number (560565615025).
Almost surely, 21121131230049 is an apocalyptic number.
It is an amenable number.
1121131230049 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121131230049 is an equidigital number, since it uses as much as digits as its factorization.
1121131230049 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 28.
The spelling of 1121131230049 in words is "one trillion, one hundred twenty-one billion, one hundred thirty-one million, two hundred thirty thousand, forty-nine".
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