Base | Representation |
---|---|
bin | 10000010100001000101… |
… | …011010000010110011011 |
3 | 10222011211121200200001122 |
4 | 100110020223100112123 |
5 | 121332034244134042 |
6 | 2215012502035455 |
7 | 143666460641435 |
oct | 20241053202633 |
9 | 3864747620048 |
10 | 1121132021147 |
11 | 3a2518886286 |
12 | 161348a18b8b |
13 | 81950b657b8 |
14 | 3c397c65655 |
15 | 1e26acca7d2 |
hex | 10508ad059b |
1121132021147 has 2 divisors, whose sum is σ = 1121132021148. Its totient is φ = 1121132021146.
The previous prime is 1121132021071. The next prime is 1121132021153. The reversal of 1121132021147 is 7411202311211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1121132021147 - 210 = 1121132020123 is a prime.
It is not a weakly prime, because it can be changed into another prime (1121132021167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560566010573 + 560566010574.
It is an arithmetic number, because the mean of its divisors is an integer number (560566010574).
Almost surely, 21121132021147 is an apocalyptic number.
1121132021147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121132021147 is an equidigital number, since it uses as much as digits as its factorization.
1121132021147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 672, while the sum is 26.
Adding to 1121132021147 its reverse (7411202311211), we get a palindrome (8532334332358).
The spelling of 1121132021147 in words is "one trillion, one hundred twenty-one billion, one hundred thirty-two million, twenty-one thousand, one hundred forty-seven".
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