Base | Representation |
---|---|
bin | 110100001101001111… |
… | …0110101010110001111 |
3 | 101201101101012212012221 |
4 | 1220122132311112033 |
5 | 3314102020041033 |
6 | 123300524040211 |
7 | 11046163342345 |
oct | 1503236652617 |
9 | 351341185187 |
10 | 112113440143 |
11 | 43602128a61 |
12 | 1988a693067 |
13 | a7593123c3 |
14 | 55d7b6b995 |
15 | 2db291712d |
hex | 1a1a7b558f |
112113440143 has 4 divisors (see below), whose sum is σ = 112223248648. Its totient is φ = 112003631640.
The previous prime is 112113440119. The next prime is 112113440167. The reversal of 112113440143 is 341044311211.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (112113440119) and next prime (112113440167).
It is a cyclic number.
It is not a de Polignac number, because 112113440143 - 225 = 112079885711 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112113440113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54902721 + ... + 54904762.
It is an arithmetic number, because the mean of its divisors is an integer number (28055812162).
Almost surely, 2112113440143 is an apocalyptic number.
112113440143 is a deficient number, since it is larger than the sum of its proper divisors (109808505).
112113440143 is a wasteful number, since it uses less digits than its factorization.
112113440143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 109808504.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 112113440143 its reverse (341044311211), we get a palindrome (453157751354).
The spelling of 112113440143 in words is "one hundred twelve billion, one hundred thirteen million, four hundred forty thousand, one hundred forty-three".
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