11211420113 has 2 divisors, whose sum is σ = 11211420114. Its totient is φ = 11211420112.

The previous prime is 11211420053. The next prime is 11211420119. The reversal of 11211420113 is 31102411211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8276814529 + 2934605584 = 90977^2 + 54172^2 .

It is an emirp because it is prime and its reverse (31102411211) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11211420113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11211420091 and 11211420100.

It is not a weakly prime, because it can be changed into another prime (11211420119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605710056 + 5605710057.

It is an arithmetic number, because the mean of its divisors is an integer number (5605710057).

Almost surely, 2^11211420113 is an apocalyptic number.

It is an amenable number.

11211420113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11211420113 is an equidigital number, since it uses as much as digits as its factorization.

11211420113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 11211420113 its reverse (31102411211), we get a palindrome (42313831324).

The spelling of 11211420113 in words is "eleven billion, two hundred eleven million, four hundred twenty thousand, one hundred thirteen".