Base | Representation |
---|---|
bin | 10000010100001001110… |
… | …101001110110000000101 |
3 | 10222011212222011220000210 |
4 | 100110021311032300011 |
5 | 121332104230211003 |
6 | 2215014433430033 |
7 | 144000114526254 |
oct | 20241165166005 |
9 | 3864788156023 |
10 | 1121151413253 |
11 | 3a2528820913 |
12 | 16135340b319 |
13 | 81954b95311 |
14 | 3c39a67279b |
15 | 1e26c85b503 |
hex | 10509d4ec05 |
1121151413253 has 16 divisors (see below), whose sum is σ = 1498075568640. Its totient is φ = 745831235184.
The previous prime is 1121151413233. The next prime is 1121151413257. The reversal of 1121151413253 is 3523141511211.
It is not a de Polignac number, because 1121151413253 - 222 = 1121147218949 is a prime.
It is a super-3 number, since 3×11211514132533 (a number of 37 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1121151413253.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1121151413257) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10150438 + ... + 10260296.
It is an arithmetic number, because the mean of its divisors is an integer number (93629723040).
Almost surely, 21121151413253 is an apocalyptic number.
It is an amenable number.
1121151413253 is a deficient number, since it is larger than the sum of its proper divisors (376924155387).
1121151413253 is a wasteful number, since it uses less digits than its factorization.
1121151413253 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 117128.
The product of its digits is 3600, while the sum is 30.
Adding to 1121151413253 its reverse (3523141511211), we get a palindrome (4644292924464).
The spelling of 1121151413253 in words is "one trillion, one hundred twenty-one billion, one hundred fifty-one million, four hundred thirteen thousand, two hundred fifty-three".
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