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112120012112131 is a prime number
BaseRepresentation
bin11001011111100011111001…
…011111101000000100000011
3112200222120100102100121022001
4121133203321133220010003
5104143433241100042011
61034243120020524431
732421255264244432
oct3137437137500403
9480876312317261
10112120012112131
11327a7914969121
12106a9739250717
134a73b443a0c1a
141d988cd5ab119
15ce67737897c1
hex65f8f97e8103

112120012112131 has 2 divisors, whose sum is σ = 112120012112132. Its totient is φ = 112120012112130.

The previous prime is 112120012112011. The next prime is 112120012112209. The reversal of 112120012112131 is 131211210021211.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 112120012112131 - 239 = 111570256298243 is a prime.

It is a super-2 number, since 2×1121200121121312 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 112120012112099 and 112120012112108.

It is not a weakly prime, because it can be changed into another prime (112120012112231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56060006056065 + 56060006056066.

It is an arithmetic number, because the mean of its divisors is an integer number (56060006056066).

Almost surely, 2112120012112131 is an apocalyptic number.

112120012112131 is a deficient number, since it is larger than the sum of its proper divisors (1).

112120012112131 is an equidigital number, since it uses as much as digits as its factorization.

112120012112131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 112120012112131 its reverse (131211210021211), we get a palindrome (243331222133342).

The spelling of 112120012112131 in words is "one hundred twelve trillion, one hundred twenty billion, twelve million, one hundred twelve thousand, one hundred thirty-one".