Base | Representation |
---|---|
bin | 10100111000100100… |
… | …11001011010111011 |
3 | 1001221101100202200111 |
4 | 22130102121122323 |
5 | 140430233044003 |
6 | 5052320045151 |
7 | 544562311255 |
oct | 123422313273 |
9 | 31841322614 |
10 | 11212003003 |
11 | 4833979893 |
12 | 220aa637b7 |
13 | 1098b25106 |
14 | 7850d8cd5 |
15 | 4594b9e6d |
hex | 29c4996bb |
11212003003 has 2 divisors, whose sum is σ = 11212003004. Its totient is φ = 11212003002.
The previous prime is 11212002973. The next prime is 11212003009. The reversal of 11212003003 is 30030021211.
It is a strong prime.
It is an emirp because it is prime and its reverse (30030021211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11212003003 - 213 = 11211994811 is a prime.
It is a super-3 number, since 3×112120030033 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (11212003009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606001501 + 5606001502.
It is an arithmetic number, because the mean of its divisors is an integer number (5606001502).
Almost surely, 211212003003 is an apocalyptic number.
11212003003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11212003003 is an equidigital number, since it uses as much as digits as its factorization.
11212003003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 13.
Adding to 11212003003 its reverse (30030021211), we get a palindrome (41242024214).
The spelling of 11212003003 in words is "eleven billion, two hundred twelve million, three thousand, three".
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